Edits history of script submission #2566 for ' Get customers search (stripe)'

• nativets

  Ap­pro­ved version

  Edit in Windmill

  Embed

  type Stripe = {
    token: string;
  };
  /**
   * Get customers search
   * Search for customers you’ve previously created using Stripe’s Search Query Language.
  Don’t use search in read-after-write flows where strict consistency is necessary. Under normal operating
  conditions, data is searchable in less than a minute. Occasionally, propagation of new or updated data can be up
  to an hour behind during outages. Search functionality is not available to merchants in India.
   */
  export async function main(
    auth: Stripe,
    expand: any,
    limit: string | undefined,
    page: string | undefined,
    query: string | undefined
  ) {
    const url = new URL(`https://api.stripe.com/v1/customers/search`);
    for (const [k, v] of [
      ["limit", limit],
      ["page", page],
      ["query", query],
    ]) {
      if (v !== undefined && v !== "") {
        url.searchParams.append(k, v);
      }
    }
    encodeParams({ expand }).forEach((v, k) => {
      if (v !== undefined && v !== "") {
        url.searchParams.append(k, v);
      }
    });
    const response = await fetch(url, {
      method: "GET",
      headers: {
        "Content-Type": "application/x-www-form-urlencoded",
        Authorization: "Bearer " + auth.token,
      },
      body: undefined,
    });
    if (!response.ok) {
      const text = await response.text();
      throw new Error(`${response.status} ${text}`);
    }
    return await response.json();
  }
  
  function encodeParams(o: any) {
    function iter(o: any, path: string) {
      if (Array.isArray(o)) {
        o.forEach(function (a) {
          iter(a, path + "[]");
        });
        return;
      }
      if (o !== null && typeof o === "object") {
        Object.keys(o).forEach(function (k) {
          iter(o[k], path + "[" + k + "]");
        });
        return;
      }
      data.push(path + "=" + o);
    }
    const data: string[] = [];
    Object.keys(o).forEach(function (k) {
      if (o[k] !== undefined) {
        iter(o[k], k);
      }
    });
    return new URLSearchParams(data.join("&"));
  }
  

  Submitted by hugo697 74 days ago

• nativets

  Edit in Windmill

  Embed

  type Stripe = {
    token: string;
  };
  /**
   * Get customers search
   * <p>Search for customers you’ve previously created using Stripe’s <a href="/docs/search#search-query-language">Search Query Language</a>.
  Don’t use search in read-after-write flows where strict consistency is necessary. Under normal operating
  conditions, data is searchable in less than a minute. Occasionally, propagation of new or updated data can be up
  to an hour behind during outages. Search functionality is not available to merchants in India.</p>
   */
  export async function main(
    auth: Stripe,
    expand: any,
    limit: string | undefined,
    page: string | undefined,
    query: string | undefined
  ) {
    const url = new URL(`https://api.stripe.com/v1/customers/search`);
    for (const [k, v] of [
      ["limit", limit],
      ["page", page],
      ["query", query],
    ]) {
      if (v !== undefined && v !== "") {
        url.searchParams.append(k, v);
      }
    }
    encodeParams({ expand }).forEach((v, k) => {
      if (v !== undefined && v !== "") {
        url.searchParams.append(k, v);
      }
    });
    const response = await fetch(url, {
      method: "GET",
      headers: {
        "Content-Type": "application/x-www-form-urlencoded",
        Authorization: "Bearer " + auth.token,
      },
      body: undefined,
    });
    if (!response.ok) {
      const text = await response.text();
      throw new Error(`${response.status} ${text}`);
    }
    return await response.json();
  }
  
  function encodeParams(o: any) {
    function iter(o: any, path: string) {
      if (Array.isArray(o)) {
        o.forEach(function (a) {
          iter(a, path + "[]");
        });
        return;
      }
      if (o !== null && typeof o === "object") {
        Object.keys(o).forEach(function (k) {
          iter(o[k], path + "[" + k + "]");
        });
        return;
      }
      data.push(path + "=" + o);
    }
    const data: string[] = [];
    Object.keys(o).forEach(function (k) {
      if (o[k] !== undefined) {
        iter(o[k], k);
      }
    });
    return new URLSearchParams(data.join("&"));
  }
  

  Submitted by hugo697 202 days ago