Edits history of script submission #2808 for ' Get customers customer cards (stripe)'

• nativets

  Ap­pro­ved version

  Edit in Windmill

  Embed

  type Stripe = {
    token: string;
  };
  /**
   * Get customers customer cards
   * You can see a list of the cards belonging to a customer.
  Note that the 10 most recent sources are always available on the Customer object.
  If you need more than those 10, you can use this API method and the limit and starting_after parameters to page through additional cards.
   */
  export async function main(
    auth: Stripe,
    customer: string,
    ending_before: string | undefined,
    expand: any,
    limit: string | undefined,
    starting_after: string | undefined
  ) {
    const url = new URL(`https://api.stripe.com/v1/customers/${customer}/cards`);
    for (const [k, v] of [
      ["ending_before", ending_before],
      ["limit", limit],
      ["starting_after", starting_after],
    ]) {
      if (v !== undefined && v !== "") {
        url.searchParams.append(k, v);
      }
    }
    encodeParams({ expand }).forEach((v, k) => {
      if (v !== undefined && v !== "") {
        url.searchParams.append(k, v);
      }
    });
    const response = await fetch(url, {
      method: "GET",
      headers: {
        "Content-Type": "application/x-www-form-urlencoded",
        Authorization: "Bearer " + auth.token,
      },
      body: undefined,
    });
    if (!response.ok) {
      const text = await response.text();
      throw new Error(`${response.status} ${text}`);
    }
    return await response.json();
  }
  
  function encodeParams(o: any) {
    function iter(o: any, path: string) {
      if (Array.isArray(o)) {
        o.forEach(function (a) {
          iter(a, path + "[]");
        });
        return;
      }
      if (o !== null && typeof o === "object") {
        Object.keys(o).forEach(function (k) {
          iter(o[k], path + "[" + k + "]");
        });
        return;
      }
      data.push(path + "=" + o);
    }
    const data: string[] = [];
    Object.keys(o).forEach(function (k) {
      if (o[k] !== undefined) {
        iter(o[k], k);
      }
    });
    return new URLSearchParams(data.join("&"));
  }
  

  Submitted by hugo697 368 days ago

• nativets

  Edit in Windmill

  Embed

  type Stripe = {
    token: string;
  };
  /**
   * Get customers customer cards
   * You can see a list of the cards belonging to a customer.
  Note that the 10 most recent sources are always available on the Customer object.
  If you need more than those 10, you can use this API method and the limit and starting_after parameters to page through additional cards.
   */
  export async function main(
    auth: Stripe,
    customer: string,
    ending_before: string | undefined,
    expand: any,
    limit: string | undefined,
    starting_after: string | undefined
  ) {
    const url = new URL(`https://api.stripe.com/v1/customers/${customer}/cards`);
    for (const [k, v] of [
      ["ending_before", ending_before],
      ["limit", limit],
      ["starting_after", starting_after],
    ]) {
      if (v !== undefined && v !== "") {
        url.searchParams.append(k, v);
      }
    }
    encodeParams({ expand }).forEach((v, k) => {
      if (v !== undefined && v !== "") {
        url.searchParams.append(k, v);
      }
    });
    const response = await fetch(url, {
      method: "GET",
      headers: {
        "Content-Type": "application/x-www-form-urlencoded",
        Authorization: "Bearer " + auth.token,
      },
      body: undefined,
    });
    if (!response.ok) {
      const text = await response.text();
      throw new Error(`${response.status} ${text}`);
    }
    return await response.json();
  }
  
  function encodeParams(o: any) {
    function iter(o: any, path: string) {
      if (Array.isArray(o)) {
        o.forEach(function (a) {
          iter(a, path + "[]");
        });
        return;
      }
      if (o !== null && typeof o === "object") {
        Object.keys(o).forEach(function (k) {
          iter(o[k], path + "[" + k + "]");
        });
        return;
      }
      data.push(path + "=" + o);
    }
    const data: string[] = [];
    Object.keys(o).forEach(function (k) {
      if (o[k] !== undefined) {
        iter(o[k], k);
      }
    });
    return new URLSearchParams(data.join("&"));
  }
  

  Submitted by hugo697 795 days ago

• nativets

  Edit in Windmill

  Embed

  type Stripe = {
    token: string;
  };
  /**
   * Get customers customer cards
   * <p>You can see a list of the cards belonging to a customer.
  Note that the 10 most recent sources are always available on the <code>Customer</code> object.
  If you need more than those 10, you can use this API method and the <code>limit</code> and <code>starting_after</code> parameters to page through additional cards.</p>
   */
  export async function main(
    auth: Stripe,
    customer: string,
    ending_before: string | undefined,
    expand: any,
    limit: string | undefined,
    starting_after: string | undefined
  ) {
    const url = new URL(`https://api.stripe.com/v1/customers/${customer}/cards`);
    for (const [k, v] of [
      ["ending_before", ending_before],
      ["limit", limit],
      ["starting_after", starting_after],
    ]) {
      if (v !== undefined && v !== "") {
        url.searchParams.append(k, v);
      }
    }
    encodeParams({ expand }).forEach((v, k) => {
      if (v !== undefined && v !== "") {
        url.searchParams.append(k, v);
      }
    });
    const response = await fetch(url, {
      method: "GET",
      headers: {
        "Content-Type": "application/x-www-form-urlencoded",
        Authorization: "Bearer " + auth.token,
      },
      body: undefined,
    });
    if (!response.ok) {
      const text = await response.text();
      throw new Error(`${response.status} ${text}`);
    }
    return await response.json();
  }
  
  function encodeParams(o: any) {
    function iter(o: any, path: string) {
      if (Array.isArray(o)) {
        o.forEach(function (a) {
          iter(a, path + "[]");
        });
        return;
      }
      if (o !== null && typeof o === "object") {
        Object.keys(o).forEach(function (k) {
          iter(o[k], path + "[" + k + "]");
        });
        return;
      }
      data.push(path + "=" + o);
    }
    const data: string[] = [];
    Object.keys(o).forEach(function (k) {
      if (o[k] !== undefined) {
        iter(o[k], k);
      }
    });
    return new URLSearchParams(data.join("&"));
  }
  

  Submitted by hugo697 922 days ago