Edits history of script submission #2847 for ' Get customers customer subscriptions (stripe)'

• nativets

  Ap­pro­ved version

  Edit in Windmill

  Embed

  type Stripe = {
    token: string;
  };
  /**
   * Get customers customer subscriptions
   * You can see a list of the customer’s active subscriptions. Note that the 10 most recent active subscriptions are always available by default on the customer object. If you need more than those 10, you can use the limit and starting_after parameters to page through additional subscriptions.
   */
  export async function main(
    auth: Stripe,
    customer: string,
    ending_before: string | undefined,
    expand: any,
    limit: string | undefined,
    starting_after: string | undefined
  ) {
    const url = new URL(
      `https://api.stripe.com/v1/customers/${customer}/subscriptions`
    );
    for (const [k, v] of [
      ["ending_before", ending_before],
      ["limit", limit],
      ["starting_after", starting_after],
    ]) {
      if (v !== undefined && v !== "") {
        url.searchParams.append(k, v);
      }
    }
    encodeParams({ expand }).forEach((v, k) => {
      if (v !== undefined && v !== "") {
        url.searchParams.append(k, v);
      }
    });
    const response = await fetch(url, {
      method: "GET",
      headers: {
        "Content-Type": "application/x-www-form-urlencoded",
        Authorization: "Bearer " + auth.token,
      },
      body: undefined,
    });
    if (!response.ok) {
      const text = await response.text();
      throw new Error(`${response.status} ${text}`);
    }
    return await response.json();
  }
  
  function encodeParams(o: any) {
    function iter(o: any, path: string) {
      if (Array.isArray(o)) {
        o.forEach(function (a) {
          iter(a, path + "[]");
        });
        return;
      }
      if (o !== null && typeof o === "object") {
        Object.keys(o).forEach(function (k) {
          iter(o[k], path + "[" + k + "]");
        });
        return;
      }
      data.push(path + "=" + o);
    }
    const data: string[] = [];
    Object.keys(o).forEach(function (k) {
      if (o[k] !== undefined) {
        iter(o[k], k);
      }
    });
    return new URLSearchParams(data.join("&"));
  }
  

  Submitted by hugo697 291 days ago

• nativets

  Edit in Windmill

  Embed

  type Stripe = {
    token: string;
  };
  /**
   * Get customers customer subscriptions
   * <p>You can see a list of the customer’s active subscriptions. Note that the 10 most recent active subscriptions are always available by default on the customer object. If you need more than those 10, you can use the limit and starting_after parameters to page through additional subscriptions.</p>
   */
  export async function main(
    auth: Stripe,
    customer: string,
    ending_before: string | undefined,
    expand: any,
    limit: string | undefined,
    starting_after: string | undefined
  ) {
    const url = new URL(
      `https://api.stripe.com/v1/customers/${customer}/subscriptions`
    );
    for (const [k, v] of [
      ["ending_before", ending_before],
      ["limit", limit],
      ["starting_after", starting_after],
    ]) {
      if (v !== undefined && v !== "") {
        url.searchParams.append(k, v);
      }
    }
    encodeParams({ expand }).forEach((v, k) => {
      if (v !== undefined && v !== "") {
        url.searchParams.append(k, v);
      }
    });
    const response = await fetch(url, {
      method: "GET",
      headers: {
        "Content-Type": "application/x-www-form-urlencoded",
        Authorization: "Bearer " + auth.token,
      },
      body: undefined,
    });
    if (!response.ok) {
      const text = await response.text();
      throw new Error(`${response.status} ${text}`);
    }
    return await response.json();
  }
  
  function encodeParams(o: any) {
    function iter(o: any, path: string) {
      if (Array.isArray(o)) {
        o.forEach(function (a) {
          iter(a, path + "[]");
        });
        return;
      }
      if (o !== null && typeof o === "object") {
        Object.keys(o).forEach(function (k) {
          iter(o[k], path + "[" + k + "]");
        });
        return;
      }
      data.push(path + "=" + o);
    }
    const data: string[] = [];
    Object.keys(o).forEach(function (k) {
      if (o[k] !== undefined) {
        iter(o[k], k);
      }
    });
    return new URLSearchParams(data.join("&"));
  }
  

  Submitted by hugo697 419 days ago