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Get application fees

by
Published Oct 30, 2023

Returns a list of application fees you’ve previously collected. The application fees are returned in sorted order, with the most recent fees appearing first.

Script stripe Verified

The script

Submitted by hugo697 Typescript (fetch-only)
Verified 398 days ago
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type Stripe = {
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  token: string;
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};
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/**
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 * Get application fees
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 * Returns a list of application fees you’ve previously collected. The application fees are returned in sorted order, with the most recent fees appearing first.
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 */
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export async function main(
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  auth: Stripe,
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  charge: string | undefined,
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  created: any,
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  ending_before: string | undefined,
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  expand: any,
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  limit: string | undefined,
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  starting_after: string | undefined
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) {
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  const url = new URL(`https://api.stripe.com/v1/application_fees`);
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  for (const [k, v] of [
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    ["charge", charge],
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    ["ending_before", ending_before],
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    ["limit", limit],
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    ["starting_after", starting_after],
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  ]) {
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    if (v !== undefined && v !== "") {
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      url.searchParams.append(k, v);
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    }
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  }
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  encodeParams({ created, expand }).forEach((v, k) => {
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    if (v !== undefined && v !== "") {
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      url.searchParams.append(k, v);
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    }
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  });
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  const response = await fetch(url, {
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    method: "GET",
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    headers: {
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      "Content-Type": "application/x-www-form-urlencoded",
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      Authorization: "Bearer " + auth.token,
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    },
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    body: undefined,
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  });
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  if (!response.ok) {
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    const text = await response.text();
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    throw new Error(`${response.status} ${text}`);
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  }
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  return await response.json();
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}
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function encodeParams(o: any) {
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  function iter(o: any, path: string) {
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    if (Array.isArray(o)) {
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      o.forEach(function (a) {
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        iter(a, path + "[]");
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      });
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      return;
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    }
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    if (o !== null && typeof o === "object") {
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      Object.keys(o).forEach(function (k) {
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        iter(o[k], path + "[" + k + "]");
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      });
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      return;
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    }
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    data.push(path + "=" + o);
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  }
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  const data: string[] = [];
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  Object.keys(o).forEach(function (k) {
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    if (o[k] !== undefined) {
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      iter(o[k], k);
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    }
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  });
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  return new URLSearchParams(data.join("&"));
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}
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