Create a file in S3 (Python)

#requirements:

wmill>=1.251.7

# Details on S3 integration at https://www.windmill.dev/docs/core_concepts/persistent_storage/large_data_files

import wmill

from wmill import S3Object

def main(s3_file_path: str):

    s3_file_output = S3Object(s3=s3_file_path)

    file_content = b"Hello Windmill!"

	# file_content can be either bytes or a BufferedReader

    file_content = wmill.write_s3_file(s3_file_output, file_content)

    return s3_file_output